Question

設集合M={x|(x+3)(x-2)<0}，N ={x|1≤x≤3},則M∩N =(    )

A．[1,2)

B．[1,2]

C．( 2,3]

D．[2,3]

Answer 1

A

M={x|(x+3)(x-2)<0}="(-3,2)," N ={x|1≤x≤3}故M∩N =[1,2)。